b^2+10=4b

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Solution for b^2+10=4b equation:


Simplifying
b2 + 10 = 4b

Reorder the terms:
10 + b2 = 4b

Solving
10 + b2 = 4b

Solving for variable 'b'.

Reorder the terms:
10 + -4b + b2 = 4b + -4b

Combine like terms: 4b + -4b = 0
10 + -4b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -4b + -10 + b2 = 0 + -10

Reorder the terms:
10 + -10 + -4b + b2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -4b + b2 = 0 + -10
-4b + b2 = 0 + -10

Combine like terms: 0 + -10 = -10
-4b + b2 = -10

The b term is -4b.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4b + 4 + b2 = -10 + 4

Reorder the terms:
4 + -4b + b2 = -10 + 4

Combine like terms: -10 + 4 = -6
4 + -4b + b2 = -6

Factor a perfect square on the left side:
(b + -2)(b + -2) = -6

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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